Question

Sin Θ × tan Θ + tan²Θ = ?
a. cot²Θ(1 + tan Θ) b. tan²Θ(1 + cosΘ) c. tan²Θ(1 + sin Θ) d. cot² (1+ sinΘ )

Answer 1

Answer:

b

Step-by-step explanation:

= sin theta*tan theta + tan^2 theta

=sin theta (1/cot theta)+ 1/cot ^2theta

= sin theta cot theta /cot^2theta +1/cot^ theta

=sin theta *cos theta/sin theta*cot^2 theta+1/cot^theta

=cos theta+1/cot^2theta

= tan^2 theta(1+cos theta)