sin.tetha =4/5 and the value of sin tetha . tan tetha -1/2tan^2 tetha
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Answer:
sin°=4/5, tan°=4/3,
sin°× tan°-1/2tan^2°=4/5×4/3-1/2×16/9
=16/15-8/9
=8/45
Answered by
1
Answer:
Given sinθ = 4/5
→ The value of sinθ . tanθ - 1/2 tan²θ
tanθ = 4/3
→ = 4/5 . 4/3 - 8/9 = 8/45
Hope it's helpful to you
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