Math, asked by rajsingh24, 11 months ago

SIN\theta=? ,cos\theta=?, TAN\theta=1.

SOLVE THIS. ​

Answers

Answered by Anonymous
46

Answer:

 \sin  \theta =  \frac{1}{ cosec \theta} \\  \\ coses \theta =  \frac{1}{sec \theta}   \\  \\  \tan\theta =  \frac{1}{cot \theta}  \\  \\

Answered by Shreya091
88

\huge\star{\mathfrak{\underline{\green{QueStion:-}}}}

If value of Tanθ = 1 , then find sinθand cos θ

\huge\star{\mathfrak{\underline{\green{AnSwEr}}}}

Using the trigonometric ratios;

\large\tt\ Sinθ \: = \: \frac{perpendicular}{Hypotenuse}

\large\tt\ Cosθ \: = \: \frac{Base}{Hypotenuse}

\large\tt\ Tanθ \: = \: \frac{Perpendicular}{Base}

Now, solve according to them ;

Value of Tanθ is given and that is 1 ,

\large\tt\ Tanθ \: = \: \frac{1}{1}

From this we can conclude that, Base and perpendicular both are equal to 1 ;

Using phythagorus theorem ;

\large{\boxed{\boxed{\sf{\red{ Hypotenuse^2 \: = \: Perpendicular^2 \: + \: Base^2}}}}}

Now;

\large\tt\ Hypotenuse^2 \: = \: (1)^2 \: + \: (1)^2

\large\tt\ Hypotenuse \: = \: \sqrt{2}

Conistute it ;

\large\tt\ Sinθ \: = \: \frac{1}{\sqrt{2} }

And;

\large\tt\ Cosθ \: = \: \frac{1}{\sqrt{2} }

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