Sin theata =1 then theata =
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The general solution of sin θ = 1 is θ = (4n + 1)π2, n ∈ Z. Therefore, either, 2 sin x + 3 = 0 ⇒ sin x = - 32, Which is impossible since the numerical value of sin x cannot be greater than 1.
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Answer:nπ+(-1^n)π/2
where=0,1,2...
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