sin theeta /1+cos theeta + 1+cos theeta / sin theeta =2cosec
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hope this will help you
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ashit3:
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LHS = sin^2A + 1 +cos^2A + 2cosA / sinA(1+cosA)
= 2 + 2cosA / sinA (1 + cosA)
= 2(1+ cosA) / sinA (1+ cosA)
= 2/sinA
= 2cosecA
RHS = 2cosec^2A
LHS = RHS
(note = theeta is A)
= 2 + 2cosA / sinA (1 + cosA)
= 2(1+ cosA) / sinA (1+ cosA)
= 2/sinA
= 2cosecA
RHS = 2cosec^2A
LHS = RHS
(note = theeta is A)
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