sin theeta-2 sin theeta / 2 cos ³ theeta - cos theeta = tan theeta
Answers
Answered by
3
Answer:
2cos3θ−cosθsinθ−2sin3θ
=cosθ(2cos2θ−1)sinθ(1−2sin2θ)
=cosθ.cos2θsinθ.cosθ
=cosθsinθ
=tanθ.
Answered by
1
Answer:
sinθ
Step-by-step explanation:
sinθ−2sin
3
θ
=
cosθ(2cos
2
θ−1)
sinθ(1−2sin
2
θ)
=
cosθ.cos2θ
sinθ.cosθ
=
cosθ
sinθ
=tanθ.
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