Question

sin theeta+ cos theeta = root 2 sin(90-theeta).... if anyone know plz answer​

Answer 1

Answer:

Step-by-step explanation:

Let theata be A

sinA + cosA root 2 cos (90-A)

SinA +cosA= root 2 sinA

CosA = root 2sinA - sinA

CosA = sinA (root - 1)

CosA/sinA =(root - 2)

So, cotA= root 2 -1

Hope it helps....

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Mark as a brainliest....❤

Answer 2

Answer:

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