sin theetha + cos thewtha=1 Then show that Cos theetha - sin theetha =1
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Heya buddy !
(cosθ+sinθ)^2+(cosθ−sinθ)^2=2(sin2θ+cos2θ)
⇒12+(cosθ−sinθ)^2=2×1
⇒(cosθ−sinθ)^2=2−1=1
⇒cosθ−sinθ=±1
(cosθ+sinθ)^2+(cosθ−sinθ)^2=2(sin2θ+cos2θ)
⇒12+(cosθ−sinθ)^2=2×1
⇒(cosθ−sinθ)^2=2−1=1
⇒cosθ−sinθ=±1
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