Question

Sin theta = 1/2 then Cot theta = ?

Answer 1

sin ¢ = 1/2 = Perpendicular / Hypotenuse





Perpendicular = 1 and Hypotenuse = 2.


By Pythagoras theroem,


( Hypotenuse )² = ( Perpendicular)² + ( Base )²




(2)² = (1)² + (Base)²



( Base)² = 4 - 1


Base = √3.



Therefore,

Cot ¢ = Base / Perpendicular = √3/1 = √3.

Answer 2

hello mate!.......


given.........


$take.......theta = x(here \: not \: possible \: write) \\ \\ sinx = \frac{1}{2} \\ \\ we \: know..... \\ \\ sin {}^{2} x + cos {}^{2} x = 1 \\ \\ ( \frac{1}{2} ) {}^{2} + cos {}^{2}x = 1 \\ \\ cos {}^{2} x = 1 - \frac{1}{4} \\ \\ cos {}^{2} x = \frac{3}{4} \\ \\ cosx = \frac{ \sqrt{3} }{2} \\ \\ cotx = \frac{cosx}{sinx} \\ \\ \\ cotx = \frac{ \sqrt{3} }{2} \times \frac{2}{1} \\ \\ cotx = \sqrt{3}$
HOPE IT HELPS U DEAR........