Question

sin theta/1-cos theta=1+cos theta/sin theta

Answer 1

take the lhs:-

sin theta/1-cos theta

multiply the numerator and denominator by 1+cos theta

=>sin theta *(1+cos theta)/1-cos theta*(1+cos theta)

=>sin theta*(1+cos theta)/1-cos^2theta

from sin^2theta +cos^2theta=1, we get 1-cos^2theta =sin^2theta

=>sin theta*(1+cos theta)/sin^2 theta

cancelling ,

=>1+cos theta/sin theta

therefore LHS=RHS

Hence verified..

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