sin theta / 1+ cos theta + 1+ cos theta / sin theta = 2 cosec theta
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Sin theta/1+cos theta + 1 +cos theta/ sin theta = 2 cosec theta is proved.
I am taking theta as A so that it is easy for explanation.
Step-by-step explanation:
= sin A / 1 + cos A + 1+ cos A/ sin A
= sin A ×sin A+ (1+ cos A)×(1+cos A) / sin A (1+ cos A)
Taking L.C.M. of sin A and 1+ cos A
= sin²A + (1+ cos A)²/ sin A (1+ cos A)
= sin²A + (1² + cos² A + 2 ×1××cos A) / sin A (1+ cos A )
= sin² A + 1+ cos²A + 2 cos A/ sin A (1+ cos A)
= 1+1+2 cos A/ sin A (1+ cos A)
= 2+2 cos A/ sin A (1+ cos A)
= 2( 1+ cos A) / sin A (1+ cos A)
Taking 2 common
= 2 / sin A
= 2× I/ sin A
= 2 cosec A = RHS
Hence, proved.
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