sin theta + 1 - cos theta by cos theta - 1 + sin theta is equal to 1 + sin theta by cos theta
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Answer:
Step-by-step explanation:
RHS:
dividing num and den by cos∅
=(tan∅+sec∅-1)/(1-sec∅+tan∅)
=[tan∅+sec∅-(sec²∅-tan²∅)]/(1-sec∅+tan∅) (∵sec²∅-tan²∅=1)
=(sec∅+tan∅)(1-sec∅+tan∅)/1-sec∅+tan∅)
=(sec∅+tan∅)
=(1+sin∅)/cos∅
∴Hence Proved
kuttykutty2:
tq
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