sin theta/1-cos theta = cosec theta + cot theta
Attachments:
Answers
Answered by
1
Answer:
LHS,
sin theta/1-cos theta
=sin(1+cos theta)/(1-cos theta)(1+cos theta)
=sin(1+cos theta)/1-cos^2theta
=sin(1+cos theta)/sin^2theta
[sin^2 theta+cos^2 theta=1
cos^2 theta-1=sin^2 theta]
=(1-cos theta)/sin theta
=cosec theta+cot theta
=RHS.
Hence proved.
Similar questions