Math, asked by athuuu, 11 months ago

sin theta (1+cos theta) / sin theta (1-cos theta) = sec theta +1 / sec theta-1

this is easy plz solve for 100 points ​

Answers

Answered by Anonymous
2

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Step by step solution:

Let \ theta \ =A\\\\we \ have \ to \ prove \ \frac{sin \ A(1+cos \ A)}{sin \ A(1-cos \ A}=\frac{sec \ A+1}{sec \ A-1}\\\\ L.H.S=\frac{1+cos \ A}{1-cos \ A}\\\\ L.H.S=\frac{1+\frac{1}{sec \ A} }{1-\frac{1}{sec \ A} }\\\\ L.H.S= \frac{(sec \  A+1(sec \ A)}{(sec \ A-1)((sec )}\\\\L.H.S.=\frac{(sec \ A+1)}{(sec \ A-1)}\\\\L.H.S=R.H.S\\\\Hence \ proved.

Hope it is clear to you.

Answered by rahman786khalilu
0

Step-by-step explanation:

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