(Sin theta + 1 + cos theta )( sin theta - 1 + cos theta) (sec theta cosec theta )=2
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(sin theta + 1 + cos theta) × (sin theta - 1 + cos theta) × sec theta cosec theta
[(sin theta + cos theta)²-1] × 1/cos theta sin theta
(sin (theta)² + 2sin theta cos theta + cos (theta)²-1) × 1/cos theta sin theta
(1+2sin theta cos theta -1) × 1/cos theta sin theta
sin 2 theta × 1/cos theta sin theta
2 sin theta cos theta × 1/cos theta sin theta
by reducing the expression
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Answer:
refer to the above attachment for the proof.
Attachments:
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