Math, asked by bhavyasr05, 22 hours ago

sin theta/1-cot theta+cos theta/1-than theta is equal to a.0 b.1 c. sin theta+cos theta d.sin theta-cos theta​

Answers

Answered by Anonymous
0

Answer:

 \frac{ \sin(a) }{1 -  \cot(a) }  +  \frac{ \cos(a) }{1 -  \tan(a) }  \\  = \frac{ \sin {}^{2} (a) }{ \sin  (a)  -  \cos(a) }   +  \frac{ \cos {}^{2} (a) }{ \cos(a) -  \sin(a)  }  \\  =  \frac{  \cos {}^{2} (a) -  \sin {}^{2} (a)  }{ - ( \sin(a) -  \cos(a)  } \\  =  \frac{ \sin {}^{2} (a) -  \cos {}^{2} (a)  }{ \sin(a) -  \cos(a)  } \\  = sin(a) +cos(a)

sin(a) +cos(a) is the answer hope it's helps option c

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Answered by RISINGSPAM
0

Answer:

 \frac{ \sin(a) }{1 -  \cot(a) }  +  \frac{ \cos(a) }{1 -  \tan(a) }  \\  = \frac{ \sin {}^{2} (a) }{ \sin  (a)  -  \cos(a) }   +  \frac{ \cos {}^{2} (a) }{ \cos(a) -  \sin(a)  }  \\  =  \frac{  \cos {}^{2} (a) -  \sin {}^{2} (a)  }{ - ( \sin(a) -  \cos(a)  } \\  =  \frac{ \sin {}^{2} (a) -  \cos {}^{2} (a)  }{ \sin(a) -  \cos(a)  } \\  = sin(a) +cos(a)

sin(a) +cos(a) is the answer hope it's helps option c

mark as brainlest answer

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