Question

sin theta (1+tan theta) = tan theta (sin theta +cos theta) ​

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

I am taking theta as $

:Sin $ (1 + tan $)=tan $ (sin $ + cos $)

:Sin $ + sin $ . Sin $/cos $ = sin $ . Sin $/cos $ + Sin $/cos $ .Cos $

:Sin $ + sin^2 $/cos $ = sin^2 $/cos $ + sin $

:(Sin $.cos $ + sin^2 $)/cos $ =

(Sin $.cos $ + sin^2 $)/cos $