Question

(sin theta - 2 sin^3 theta) = (2 cos^3 theta - cos theta) tan theta

Answer 1

Answer:

Step-by-step explanation:

Solve from R.H.S

(2Cos³θ - Cosθ)Tanθ

= (2Cos³θ - Cosθ) (Sinθ/Cosθ)

= (2Cos²θ - 1)Sinθ

= [2(1-Sin²θ) - 1]Sinθ

= (2-2Sin²θ - 1)Sinθ

= (1 - 2Sin²θ)Sinθ

= Sinθ - 2Sin³θ

= L.H.S