sin theta - 2 sin cube theta / 2 cos square theta - cos theta = tan theta. please prove this question?!!!!?
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Answered by
34
HELLO DEAR,
we know that:
cos 2θ = (2cos² θ - 1 )= (1 - 2sin² θ)
here,
(sinθ - 2sin³θ ) / (2cos³ θ -cos θ)
= sinθ ( 1 - 2sin² θ) / cos θ (2cos² θ - 1 )
= sin θ ×cos 2θ / cos θ × cos 2θ
= tan θ
I HOPE ITS HELP YOU DEAR,
THANKS
we know that:
cos 2θ = (2cos² θ - 1 )= (1 - 2sin² θ)
here,
(sinθ - 2sin³θ ) / (2cos³ θ -cos θ)
= sinθ ( 1 - 2sin² θ) / cos θ (2cos² θ - 1 )
= sin θ ×cos 2θ / cos θ × cos 2θ
= tan θ
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
4
Hope this answer helps you.....
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