sin theta - 2 sin cube theta upon 2 cos cube theta - cos theta is equal to tan theta
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Answer:
(sin theta- 2sin cube theta)/(2cos cube theta-cos theta)=tan theta
Step-by-step explanation:
(sin theta-2sin cube theta)/(2cos cube theta-cos theta)
=(sin theta(1-2(sin theta)^2))/(cos theta(cos theta)^2-1)
=(sin theta/cos theta)*(1- 2(1-(cos theta)^2)/(cos theta(cos theta)^2-1)
=tan theta*(1-2+2(cost theta)^2)/(cos theta)^2-1)
=tan theta*(-1+2(cos theta)^2/(cos theta)^2-1))
=tan theta*((cos theta)^2-1)/(cos theta)^2-1))
=tan theta*1
=tan theta
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tan theta- cos theta
tan theta
might be useful
thank me
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