Question

Sin theta-2sin cube theta/2cos cube theta-cos theta

Answer 1

Answer:

tan theta

Step-by-step explanation:

the answer will be...

tan theta

Answer 2

$\frac{sin \theta -2 sin^3 \theta }{2 cos^3 \theta - cos \theta } = tan \theta$

Step-by-step explanation:

Given:

$\frac{sin \theta -2 sin^3 \theta }{2 cos^3 \theta - cos \theta }$

= $\frac{sin \theta (1 - 2 sin^2 \theta)}{cos \theta (2cos^2 \theta -1)}$

= $\frac{sin \theta (1 - 2 (1-cos^2 \theta))}{cos \theta (2cos^2 \theta -1)}$

= $\frac{sin \theta (1 -2+2cos^2 \theta))}{cos \theta (2cos^2 \theta -1)}$

= $\frac{sin \theta (2cos^2 \theta-1)}{cos \theta (2cos^2 \theta -1)}$

= $\frac{sin \theta}{cos \theta}$

= tan theta