Question

sin theta -2sin3theta/2cos3theta-costheta=tan theta​

Answer 1

Answer:

$you \: mean \: this \: questin \\ \frac{sin \alpha - 2sin3 \alpha }{2cos3 \alpha - cos \alpha } = tan \alpha$

I think something is missing in this question again check the question.

Answer 2

Answer:

yeh there is somthing missing in it .  

i think it is the answer

Step-by-step explanation: