sin theta - 2sin³theta/cos theta - 2cos³ theta = tan²theta prove it
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Answer:
RHS = (2 cos^3 theta cos theta) tan
theta
= ='(2 cos^2 theta - 1) cos theta x
sin theta/ cos theta
= [2(1- sin^2 theta ) -1] sin theta
= (2-2 sin^2 theta -1 ) sin theta
= (1-2 sin^2 theta ) sin theta
= ( sin theta -2 sin^3 theta )
=LHS
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