Question

SIN THETA = 3/4

Prove that root cosec^2 theta - cot^2 theta /sec^2 theta - 1 = root7/3

Answer 1

let take tetha be x

sin x= 3/4

given

=>(cosec^2 - cot^2 /SEC^2-1)root

=>(cosec^2- cot^2 / tan^2 )root

=>(1/tan^2x)root

=>(cos^2 /sin^2)root

p=3 h=4 b=?

$b^{2} =h^{2}-p^{2}$

>$b^{2}$=16-9

=>$b^{2}$=7

=>b=$\sqrt{7}$

then cos^2 /sin^2

=>{(7/4)/(3/4)}root

=>$\sqrt{7/3}$

Answer 2

Answer:

Look here it is

Step-by-step explanation:

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