Question

Sin theta=3/5 and cos theta=4/5 find the value of sin²theta+cos²

Answer 1

Answer:

sin²x + cos²x = 1

Step-by-step explanation:

stepwise explanation is given in image

Answer 2

Answer

The value of sin²θ + cos²θ is 1

$\bf\large\underline{Given}$

• sinθ = 3/5
• cosθ = 4/5

$\bf\large\underline{To \ Find}$

• sin²θ + cos²θ

$\bf\large\underline{Solution}$

We have ,

sinθ = 3/5

cosθ = 4/5

Therefore,

$\sf \implies \sin {}^{2} \theta + \cos {}^{2} \theta = (\dfrac{3}{5} ) {}^{2} +( \dfrac{4}{5} ) {}^{2} \\ \\ \sf\implies \sin {}^{2} \theta + \cos {}^{2} \theta = \dfrac{9}{25} + \dfrac{16}{25} \\ \\ \implies \sf\sin {}^{2} \theta + \cos {}^{2} \theta = \dfrac{9 + 16}{25} \\ \\ \sf\implies \sin {}^{2} \theta + \cos {}^{2} \theta = \dfrac{25}{25} \\ \\ \sf \implies \sin {}^{2} \theta + \cos {}^{2} \theta = 1$