Question

sin theta = 3/5 and theta lies in second quadrant then value of sin 2 theta is

​

Answer 1

Answer:

Step-by-step explanation:

if sin∅ = 3/5

∵cos²∅ + sin²∅ = 1

cos∅ =$\sqrt{1-sin^2theta}$

cos∅ = $\sqrt{\frac{16}{25} }$

cos∅ =-4/5(cos is -ve in 2nd quadrant )

∵sin2∅ = 2sin∅cos∅

sin2∅ = 2×$\frac{3}{5}$×-$\frac{4}{5}$

∴sin2∅ = - $\frac{24}{25}$

please mark as brainliest

Answer 2

Answer:

answer is 6/10 I think

I don't know but Herr it ia