Question

sin theta =√3,cos theta =?
please answer me ​

Answer 1

Answer:

√-2

Step-by-step explanation:

sinθ = √3

Using identity :

sin²θ + cos²θ = 1

(√3)² + cos²θ = 1

3 + cos²θ = 1

cos²θ = 1 - 3

cos²θ = -2

cosθ = √-2

Answer 2

Answer:

hey here is your answer

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Step-by-step explanation:

$so \: here \: sin \: theta = \sqrt{3} \\ to \: find \: cos \: theta \\ applying \: now \\ sin.square \: theta + cos.square \: theta = 1 \\ ie \: cos \: square \: theta = 1 - sin \: square \: theta \\ = 1 - ( \sqrt{3})square \\ = 1 - 3 \\ = - 2$

$taking \: square \: roots \: on \: both \: sides \: \\ we \: get \\ cos \: theta = \sqrt{ - 2} \\ but \: as \: we \: know \: that \: if \: the \: roots \: of \: certain \: quadratic \: term \: are \: < 0 \\ then \: the \: roots \: are \: not \: real \: ie \: are \: imaginary \: \\ so \: such \: roots \: are \: represented \: by \: iota \: i$

$hence \: cos \: theta = \sqrt{2i} or \: - \sqrt{2i}$