Question

Sin theta = 6/10, Find the value of cos theta + Tan theta... Solve using Trigonometrical formulas ​

Answer 1

Answer:

62/40 =31/20

Step-by-step explanation:

As we now that sin theta = P/H (perpendicular/hypotenuse)

Means

P=6 and H=10

Now we find the value of base by Pythagoras theorem

So, B= 8

Then put the values on formula : -

Cos theta = B/H= 8/10

and ,

Tan theta = P/B= 6/8

now adding both ,

cos theta + tan theta = 6/10 + 6/8

= 62/20 or 31/20

May be it will help you

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Answer 2

$\sin( \alpha ) = \frac{6}{10}$

$\cos( \alpha ) = \frac{4}{5}$

$\tan( \alpha ) = \frac{3}{4}$

$\cos( \alpha ) + \tan( \alpha ) = \frac{4}{5 } + \frac{3}{4}$

$\cos( \alpha ) + \tan( \alpha ) = \frac{16 + 15}{20}$

$\cos( \alpha ) + \tan( \alpha ) = \frac{31}{20}$