Question

sin theta =a/b then cot theta=?​

Answer 1

Answer:

${sin}^{2} + {cos}^{2} =1 \\ = { (\frac{a}{b} )}^{2} + {cos}^{2} = 1 \\ {cos}^{2} = 1 - \frac{ {a}^{2} }{ {b}^{2} } \\ {cos}^{2} = \frac{ {b}^{2} - {a}^{2} }{ {b}^{2} } \\ cos = \frac{ \sqrt{ {b}^{2} - {a}^{2} } }{b}$

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