Question

sin theta and sec theta are the roots of the equation root 3 x2 + kx + 3 .Find the value to k
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Answer 1

Answer:

Step

(k+2)x²-kx+6

(k+2)3²-k(3)+6=0

(k+2)9-3k+6=0

9k+18-3k+6=0

6k+24=0

6k=-24

K=-24/6

k=-4

-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

√3x²+kx+3=0

sum of zeroes = -b/a = -k/3

product of zeroes = c/a = 3/√3

       3/√3 => (√3×√3)/√3

                 => √3

sin 60/cos 60 = tan 60

tan 60 = √3

tan theta = opposite/adjacent

opposite = √3 , adjacent = 1

hypotenuse² = adjacent² + opposite²

hypotenuse² = 1² + √3²

hypotenuse = 2

sin theta = opp/hy

               = √3/2

sec theta = hy/adj

                = 2/1 = 2

applying the value of sec theta in the equation,

√3(2)² + 2k + 3 = 0

4√3 + 2k + 3 = 0

k = (-3 - 4√3)/2