sin theta by 1 + cos theta + 1 + cos theta by sin theta is equal to 2 cosecant theta
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To prove that (sinθ/1+cosθ) + (1+cosθ/sinθ) = cosecθ
L.H.S:
(sinθ/1+cosθ) + (1+cosθ/sinθ)
By cross-multiplication,
sin²θ + (1 + cosθ)² / sinθ (1+cosθ)
Remember, sin²θ + cosθ² = 1
So when you expand,
(sin²θ + cos²θ + 1 + 2cosθ ) / sinθ (1 + cosθ)
2 + 2cosθ / sinθ ( 1+ cosθ)
2( 1 + cosθ) / sinθ ( 1 + cosθ)
2 / sin θ
2 (1/sinθ) ⇒ 2 cosecθ
R.H.S
2 cosec θ
L.H.S = R.H.S, hence proved
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