sin theta by 1_cos theta =cosec theta +cot theta
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Given.....sin theta/1-cos theta =cosec theta+cot theta
sin theta/1-cos theta* 1+cos% (multiplying both denominator and numerator by 1+cos theta)
=sin theta (1+cos theta)/1-cos2 theta
sin theta(1+cos theta)/sin2 theta .........( using the identity 1+cos2 theta=sin2 theta)
=1+costheta /sin theta
LHS= serpearte the numeratrz as they hv a common denominatrz
1/sint heta +cos theta/sin theata
=cosec theta+cot theta=RHS
Hope it helpz !!
sin theta/1-cos theta* 1+cos% (multiplying both denominator and numerator by 1+cos theta)
=sin theta (1+cos theta)/1-cos2 theta
sin theta(1+cos theta)/sin2 theta .........( using the identity 1+cos2 theta=sin2 theta)
=1+costheta /sin theta
LHS= serpearte the numeratrz as they hv a common denominatrz
1/sint heta +cos theta/sin theata
=cosec theta+cot theta=RHS
Hope it helpz !!
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