Question

sin theta=c/root of c^2+d^2 and d>0, find the values of cos theta and tan theta

Answer 1

cos theta = d/root of c^2+d^2

&

tan theta = c/d

Answer 2

cos θ = d/$\sqrt{ c^{2}+ d^{2} }$
tan θ = c/d


By equation of sin θ , we get to know that Perpendicular(P)=c and Hypotenuse(H)=  $\sqrt{ c^{2}+ d^{2} }$

and

H²=B²+P²

So B=d


Now, cos θ= B/H =d/$\sqrt{ c^{2}+ d^{2} }$
         tan θ=P/B =c/d