Question

sin(π−theta)÷cos(3π÷2−theta)+tan(−theta)÷cot(π÷2+theta)+sec(π−theta)÷cosec(π÷2−theta)=1​​

Answer 1

cos(2π−θ).sin(π+θ).tan(2π−θ)

cot(

2

π

+θ)).sin(−θ).(cotπ−θ)

=−cosecθ

(cosθ)(−sinθ)(−tanθ)

(−tanθ)(−sinθ)(−cotθ)

=−cosecθ

cosθ

cotθ

=cosecθ

cosθ

1

×

sinθ

cosθ

=

sinθ

1

1=1