Sin theta*cos(90-theta)+sin(90-theta)*cos theta
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cos(90-theta) = sin(theta) similarly sin(90-theta)= cos(theta) so that makes ur questions as
sin^2(theta) + cos^2(theta) which is equal to 1
sin^2(theta) + cos^2(theta) which is equal to 1
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sin0/ cos (90-0/)+ sin(90+0/)cos sin = tan0/
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