Question

Sin theta - cos theta = 0 then prove that sec theta = ±√2

Answer 1

hi bro happy rakshabandan

Answer 2

Here I am using A instead of theta.

Given sinA - cosA = 0

=> sinA = cosA

=> sinA = sin( 90 - A )

=> A = 90 - A

=> A + A = 90

=> 2A = 90°

=> A = 45°

Now ,

x = sec A + cosec A

= sec 45° + cosec 45°

= √2 + √2= 2√2

Therefore ,

x = 2√2