Question

sin theta - cos theta +1/sin theta - cos theta -1 =1/sec theta -tan theta
plz solve this I have boards

Answer 1

Answer:

Step-by-step explanation:

Divide all the term of LHS by cos

We get,

Tan-1+sec/tan-1-sec

Tan +sec-1/tan-sec-1

Putting value of 1

Tan+sec(tan-sec)(tan+sec)/tan -sec-1

Tan+sec(tan-sec-1)/tan-sec-1

We get,

Sec+tan

Divide n multiply by sec-tan

We get,

Sec+tan*sec-tan/sec-tan

1/sec-tan =RHS

HENCE PROVED

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