(sin theta- cos theta + 1)÷ (sin theta+ cos theta-1)
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Step-by-step explanation:
= sin theta-cos theta + 1 ÷ sin theta + cos theta-1
= sin theta-cos theta+1 /cos theta ÷ sin theta + cos theta-1/cos theta
= tan theta-1+sec theta÷tan theta + 1 -sec theta
= (tan theta+sec theta)-(sec² theta-tan² theta) ÷ tan theta+1-sec theta
= (tan theta+sec theta)-(sec theta+tan theta)(sec theta-tan theta)÷tan theta+1-sec theta
= (tan theta+sec theta)(1-sec theta+tan theta)÷tan theta+1-sec theta
= (tan theta + sec theta) Ans.
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