Question

(Sin theta+cos theta )(1-sin theta cos theta ). Can be written as

Answer 1

Step-by-step explanation:

sinθ+cosθ−sin

sinθ+cosθ−sin 2

θcosθ−sinθcos

θcosθ−sinθcos 2

θcosθ−sinθcos 2 θ

θcosθ−sinθcos 2 θ=cosθ(1−sin

θcosθ−sinθcos 2 θ=cosθ(1−sin 2

θcosθ−sinθcos 2 θ=cosθ(1−sin 2 θ)+sinθ(1−cos

θcosθ−sinθcos 2 θ=cosθ(1−sin 2 θ)+sinθ(1−cos 2

θcosθ−sinθcos 2 θ=cosθ(1−sin 2 θ)+sinθ(1−cos 2 θ)=cos

θcosθ−sinθcos 2 θ=cosθ(1−sin 2 θ)+sinθ(1−cos 2 θ)=cos 3

θcosθ−sinθcos 2 θ=cosθ(1−sin 2 θ)+sinθ(1−cos 2 θ)=cos 3 θ+sin

θcosθ−sinθcos 2 θ=cosθ(1−sin 2 θ)+sinθ(1−cos 2 θ)=cos 3 θ+sin 3

θcosθ−sinθcos 2 θ=cosθ(1−sin 2 θ)+sinθ(1−cos 2 θ)=cos 3 θ+sin 3 θ.

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