sin theta - cos theta =√2
Answers
Answered by
0
sin theta - cos theta=√2
by multiplying 1/√2 in both sides....
1/√2 sin theta - 1/√2 cos theta=1
we know 1/√2=cosπ/4=sinπ/4
so....
sin π/4 sin theta - cos π/4 cos theta =1
as sinAsinB-cosAcosB=cos(A+B)
cos (π/4 +theta)=1
cos (π/4+theta)=cos2nπ
π/4 +theta=2nπ
theta=2nπ-π/4
where n is Integer or €Z
by multiplying 1/√2 in both sides....
1/√2 sin theta - 1/√2 cos theta=1
we know 1/√2=cosπ/4=sinπ/4
so....
sin π/4 sin theta - cos π/4 cos theta =1
as sinAsinB-cosAcosB=cos(A+B)
cos (π/4 +theta)=1
cos (π/4+theta)=cos2nπ
π/4 +theta=2nπ
theta=2nπ-π/4
where n is Integer or €Z
Answered by
0
2nπ-π/4 IS THE CORRECT ANSWER
Similar questions