Question

(sin theta + cos theta)²+(sin theta-cos theta)²​

Answer 1

Answer:

Step-by-step explanation:

(sinθ+cosθ) ^2  +(sinθ−cosθ)  ^2

  =(sin  ^2  θ+cos  ^2  θ+2sinθcosθ)+(sin  ^2  θ+cos  ^2  θ−2sinθcosθ)  

=(1+2sinθcosθ)+(1−2sinθcosθ)  

=1+2sinθcosθ+1−2sinθcosθ  

=1+1=2  

∴(sinθ+cosθ)  ^2  +(sinθ−cosθ)  ^2

=2

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