Question

Sin theta +
cos theta
=2
. Then
sin^ntheta+cosec^n theta​

Answer 1

Answer:

sin theta + cos theta =2

sin theta + 1/sin theta =2

sin²theta + 1 = 2 sin theta

sin²theta - 2 sin theta + 1 = 0

(sin theta - 1)² = 0

sin theta = 1. so, cosec theta is also 1

now, sin n theta + cosec n theta =

1 + 1 = 2