Question

Sin theta =cos(theta -6) find of the value fo theta

Answer 1

$\sin( \alpha ) = \cos( \alpha - 6) \\ \sin( \alpha ) = \sin(90 - ( \alpha - 6)) \\ \sin( \alpha ) = \sin(96 - \alpha ) \\ \alpha = 96 - \alpha \\ 2 \alpha = 96 \\ \alpha = 48$