Math, asked by vanshikasonkar923, 10 months ago

sin theta +cos theta =m and sec theta +cosec theta=n then n(m+1)(m-1)=?

Answers

Answered by keren777
0

Step-by-step explanation:

  • m = sin∅ + cos∅
  • n = sec∅ + cosec∅
  • n(m+1)(m-1)=?

n (m+1) (m-1)

= sec∅+cosec∅ [(sin∅+cos∅) +1] [(sin∅+cos∅)-1]

= sec+cosec∅ (1+1) (1-1)

....(since, sin∅+ cos∅=1)

= sec∅+cosec∅ (2) (0)

= 0

n(m+1)(m-1)=0

I think this should be the answer....

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