sin theta +cos theta =m and sec theta +cosec theta=n then n(m+1)(m-1)=?
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Step-by-step explanation:
- m = sin∅ + cos∅
- n = sec∅ + cosec∅
- n(m+1)(m-1)=?
n (m+1) (m-1)
= sec∅+cosec∅ [(sin∅+cos∅) +1] [(sin∅+cos∅)-1]
= sec∅+cosec∅ (1+1) (1-1)
....(since, sin∅+ cos∅=1)
= sec∅+cosec∅ (2) (0)
= 0
n(m+1)(m-1)=0
I think this should be the answer....
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