sin theta +cos theta =p. then find sin theta in terms of p
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Answer:
Given, sinΘ=
q
p
sinΘ=
H
P
=
q
p
Now, by Pythagoras Theorem,
H
2
=P
2
+B
2
q
2
=p
2
+B
2
B=
q
2
−p
2
sinΘ+cosΘ=
H
P
+
H
B
=
q
p
+
q
q
2
−p
2
=
q
p+
q
2
−p
2
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