Question

sin theta + cos theta
/root under of 1 + sin 2 theta
plz help meee ​

Answer 1

Answer:

sin theta + cos theta

/root under of 1 + sin 2 theta

= sin theta + cos theta

/root under of (sin^2theta + cos^2theta) + sin 2 theta

= sin theta + cos theta

/root under of (sin theta + cos theta)^2

= sin theta + cos theta

/(sin theta + cos theta)

= 1