Question

sin theta + cos theta= root2 cos(90-theta).
Then find the value of 'cot theta'?​

Answer 1

sinO +cosO = root2 cos(90-O)

cotO=?

Step-by-step explanation:

cosO + sinO = √2(sinO)

cosO = √2(sinO)-sinO

cosO = sinO(√2- 1)

cosO/sinO= (√2- 1)

cotO = √2- 1

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