(sin theta+cos theta) (tan theta + cot theta) =sec theta+ cosec theta
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Answer:
(sin theta + cos theta ) (sin theta/cos theta + cos theta / sin theta)
(sin theta + cos theta ) ( sin² theta + cos² theta)
___________________ (LCM of sin theta, cos theta)
sin theta cos theta
(sin theta + cos theta) (1)/sin theta cos theta
[sin theta/sin theta cos theta + cos theta/sin theta cos theta]
sec theta + cosec theta
Hence, proved.
Answered by
1
Answer:
hopefully the solution will satisfy
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