Question

Sin theta+cosec theta= 2 find sin^2 + cosec^2 without using identities

Answer 1

Answer:

$\sin^{2} ( \alpha ) + \csc ^{2} ( \alpha ) = 2$

Step-by-step explanation:

For simplicity I'm taking theta as alpha

$\sin( \alpha ) + \csc( \alpha ) = \sin( \alpha ) + \frac{1}{ \sin( \alpha ) }$

Now squaring on RHS, we get:

$( \sin( \alpha ) + \frac{1}{ \sin( \alpha ) } )^{2} = ( \sin^{2} ( \alpha ) + \frac{1}{ \sin^{2} ( \alpha ) } + 2)$

$4 = \sin^{2} ( \alpha ) + \frac{1}{ \sin ^{2} ( \alpha ) } + 2$

$\sin^{2} ( \alpha ) + \frac{1}{ \sin ^{2} ( \alpha ) } = 2$

$\sin^{2} ( \alpha ) + \csc ^{2} ( \alpha ) = 2$

Answer 2

Answer:

The above pic is the answer...plz follow it...Gud luck...