sin theta +cosec theta =2 then find 1/sin1000 theta +sin1000 theta
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if 1000 is the power of sin then solution
sunheta+1/sunheta=2
sin2theta+1-2sintheta=0
(sintheta-1) square=0
sin theta =1
cosectheta=1
so sin power 1000+cosecpower1000=2
sunheta+1/sunheta=2
sin2theta+1-2sintheta=0
(sintheta-1) square=0
sin theta =1
cosectheta=1
so sin power 1000+cosecpower1000=2
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